Check sibling questions

Find the value(s) of k for which the quadratic equation

x 2 + 2√2 kx + 18 = 0 has equal roots


Transcript

Question 20 Find the value(s) of k for which the quadratic equation x2 + 2√2 π‘˜π‘₯ + 18 = 0 has equal roots x2 + 2√2 π‘˜π‘₯ + 18 = 0 Comparing equation with ax2 + bx + c = 0 a = 1, b = 2√2k , c = 18 Since the equation has 2 equal roots, D = 0 b2 – 4ac = 0 Putting values (2√2k)2 – 4 Γ— 1 Γ— 18 = 0 22 Γ— (√2)^2Γ— k2 – 72 = 0 4 Γ— 2 Γ— k2 = 72 8k2 = 72 k2 = 72/8 k2 = 9 k = Β± √9 k = Β± 3

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo