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  If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ ≠ 90°) then the value of tan πœƒ  is

(a) √2 − 1  (b) √2 + 1  (c) √2  (d) − √2


Transcript

Question 6 If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ β‰  90Β°) then the value of tan πœƒ is (a) √2 βˆ’ 1 (b) √2 + 1 (c) √2 (d) βˆ’ √2 Given sin πœƒ + cos πœƒ = √2 cos πœƒ Dividing both sides by cos ΞΈ (sinβ‘πœƒ + cosβ‘πœƒ)/cosβ‘πœƒ = (√2 cosβ‘πœƒ)/cosβ‘πœƒ sinβ‘πœƒ/cosβ‘πœƒ +cosβ‘πœƒ/cosβ‘πœƒ =√2 tan πœƒ+1=√2 tan πœƒ=√2βˆ’1 ∴ Option (a) is correct

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo