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If triangle ABC is right angled at C, then the value of sec (A + B) is

(a) 0        (b) 1          (c) 2/√3        (d) not defined


Transcript

Question 5 If triangle ABC is right angled at C, then the value of sec (A + B) is (a) 0 (b) 1 (c) 2/√3 (d) not defined In Δ ABC Sum of angles = 180° ∠ A + ∠ B + ∠ C = 180° Given Δ ABC is right angled at C, So, ∠ C = 90° Therefore, our equation becomes ∠ A + ∠ B + 90° = 180° ∠ A + ∠ B = 180° – 90° ∠ A + ∠ B = 90° Now, sec (A + B) = sec 90° = 1/cos⁡〖90°〗 = 1/0 = Not defined ∴ Correct answer is option (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo