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Solve 2x + 3y = 11 and x − 2y = −12 algebraically and hence find the value of ‘m’ for which y = mx + 3.

 


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Question 34 Solve 2x + 3y = 11 and x − 2y = −12 algebraically and hence find the value of ‘m’ for which y = mx + 3. Given 2x + 3y = 11 x − 2y = −12 From equation (2) x – 2y = –12 x = –12 + 2y Putting value of x in (1) 2x + 3y = 11 2(–12 + 2y) + 3y = 11 –24 + 4y + 3y = 11 –24 + 7y = 11 7y = 11 + 24 7y = 35 y = 35/7 y = 5 Putting y = 5 in (2) x – 2y = –12 x – 2(5) = –12 x – 10 = –12 x = –12 + 10 x = –2 So, x = –2, y = 5 is the solution of the equations Now, we need to value for ‘m’ where y = mx + 3. Putting value of x and y in the equation y = mx + 3 5 = –2m + 3 5 – 3 = –2m 2 = –2m –2m = 2 m = 2/(−2) m = –1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo