Letβs consider the matrix

It has 2 rows & 2 columns

So, we write the order as

And,

Β 3, 2, 1, 4 are elements of matrix A

Β

We write the matrix A as

Where

a
_{
11
}
β element in 1st row, 1st column

a
_{
12
}
β element in 1st row, 2nd column

a
_{
21
}
β element in 2nd row, 1st column

a
_{
22
}
β element in 2nd row, 2nd column

Β

So,

Β Β a
_{
11
}
= 3

Β Β a
_{
12
}
= 2

Β Β a
_{
21
}
= 1

Β Β a
_{
22
}
= 4

Β

For matrix

Β

It has 3 rows & 2 columns

So, the order is 3 Γ 2.

Β

We write matrix B as

Β

Similarly,

Β

## Create a 4 Γ 3 matrix where elements are given by

##
a
_{
ij
}
= i + j

Β

A 4 Γ 3 matrix looks like

Now,

a
_{
11
}
= 1 + 1 = 2

a
_{
12
}
= 1 + 2 = 3

a
_{
13
}
= 1 + 3 = 4

a
_{
21
}
= 2 + 1 = 3

a
_{
22
}
= 2 + 2 = 4

a
_{
23
}
= 2 + 3 = 5

a
_{
32
}
= 3 + 2 = 5

a
_{
33
}
= 3 + 3 = 6

a
_{
41
}
= 4 + 1 = 5

a
_{
42
}
= 4 + 2 = 5

a
_{
43
}
= 4 + 3 = 7

Β

So, our matrix is

Β