Letβs consider the matrix
It has 2 rows & 2 columns
So, we write the order as
And,
Β 3, 2, 1, 4 are elements of matrix A
Β
We write the matrix A as
Where
a 11 β element in 1st row, 1st column
a 12 β element in 1st row, 2nd column
a 21 β element in 2nd row, 1st column
a 22 β element in 2nd row, 2nd column
Β
So,
Β Β a 11 = 3
Β Β a 12 = 2
Β Β a 21 = 1
Β Β a 22 = 4
Β
For matrix
Β
It has 3 rows & 2 columns
So, the order is 3 Γ 2.
Β
We write matrix B as
Β
Similarly,
Β
Create a 4 Γ 3 matrix where elements are given by
a ij = i + j
Β
A 4 Γ 3 matrix looks like
Now,
a 11 = 1 + 1 = 2
a 12 = 1 + 2 = 3
a 13 = 1 + 3 = 4
a 21 = 2 + 1 = 3
a 22 = 2 + 2 = 4
a 23 = 2 + 3 = 5
a 32 = 3 + 2 = 5
a 33 = 3 + 3 = 6
a 41 = 4 + 1 = 5
a 42 = 4 + 2 = 5
a 43 = 4 + 3 = 7
Β
So, our matrix is
Β
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