Check sibling questions

Let’s consider the matrix

1.jpg

It has 2 rows & 2 columns

So, we write the order as

Order of a Matrix - Part 2

And,

  3, 2, 1, 4 are elements of matrix A

 

We write the matrix A as

Order of a Matrix - Part 3

Where

a 11 → element in 1st row, 1st column

a 12 → element in 1st row, 2nd column

a 21 → element in 2nd row, 1st column

a 22 → element in 2nd row, 2nd column

 

So,

    a 11 = 3

    a 12 = 2

    a 21 = 1

    a 22 = 4

 

For matrix

Order of a Matrix - Part 4

 

It has 3 rows & 2 columns

So, the order is 3 × 2.

 

We write matrix B as

Order of a Matrix - Part 5

 

Similarly,

Order of a Matrix - Part 6

 

Create a 4 × 3 matrix where elements are given by

a ij = i + j

 

A 4 × 3 matrix looks like

Order of a Matrix - Part 7

Now,

a 11 = 1 + 1 = 2

a 12 = 1 + 2 = 3

a 13 = 1 + 3 = 4

a 21 = 2 + 1 = 3

a 22 = 2 + 2 = 4

a 23 = 2 + 3 = 5

a 32 = 3 + 2 = 5

a 33 = 3 + 3 = 6

a 41 = 4 + 1 = 5

a 42 = 4 + 2 = 5

a 43 = 4 + 3 = 7

 

So, our matrix is

Order of a Matrix - Part 8

 


Transcript

A = [■8(3&2@1&4)] 2 × 2 Rows Column And, 3, 2, 1, 4 are elements of matrix A A = [■8(𝑎_11&𝑎_12@𝑎_21&𝑎_22 )] B = [■8(3&2@1&4@5&3)] B = [■8(3&2@1&4@5&3)]_(3 × 2) Matrix Order [■8(9&5&2@1&8&5@3&1&6)] 3 × 3 [■8(1&2&5&8&𝑥&𝑧)] 1 × 6 [■8(5@9@3@𝑦@tan^(−1)⁡𝑥 )] 5 × 1 [■8(sin⁡𝑥&cos⁡𝑥&tan⁡𝑥&cot⁡𝑥@sin⁡𝑦&cos⁡𝑦&tan⁡𝑦&cot⁡𝑦@sin⁡𝑧&cos⁡𝑧&tan⁡𝑧&cot⁡𝑧 )] 3 × 4 A = [■8(𝑎_11&𝑎_12&𝑎_13@𝑎_21&𝑎_22&𝑎_23@𝑎_31&𝑎_32&𝑎_33@𝑎_41&𝑎_42&𝑎_43 )] A = [■8(2&3&4@3&4&5@4&5&6@5&6&7)] A = [■8(2&3&4@3&4&5@4&5&6@5&6&7)]

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.