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Let’s consider the matrix

1.jpg

It has 2 rows & 2 columns

So, we write the order as

Order of a Matrix - Part 2

And,

  3, 2, 1, 4 are elements of matrix A

 

We write the matrix A as

Order of a Matrix - Part 3

Where

a 11 → element in 1st row, 1st column

a 12 → element in 1st row, 2nd column

a 21 → element in 2nd row, 1st column

a 22 → element in 2nd row, 2nd column

 

So,

    a 11 = 3

    a 12 = 2

    a 21 = 1

    a 22 = 4

 

For matrix

Order of a Matrix - Part 4

 

It has 3 rows & 2 columns

So, the order is 3 × 2.

 

We write matrix B as

Order of a Matrix - Part 5

 

Similarly,

Order of a Matrix - Part 6

 

Create a 4 × 3 matrix where elements are given by

a ij = i + j

 

A 4 × 3 matrix looks like

Order of a Matrix - Part 7

Now,

a 11 = 1 + 1 = 2

a 12 = 1 + 2 = 3

a 13 = 1 + 3 = 4

a 21 = 2 + 1 = 3

a 22 = 2 + 2 = 4

a 23 = 2 + 3 = 5

a 32 = 3 + 2 = 5

a 33 = 3 + 3 = 6

a 41 = 4 + 1 = 5

a 42 = 4 + 2 = 5

a 43 = 4 + 3 = 7

 

So, our matrix is

Order of a Matrix - Part 8

 

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Transcript

A = [β– 8(3&2@1&4)] 2 Γ— 2 Rows Column And, 3, 2, 1, 4 are elements of matrix A A = [β– 8(π‘Ž_11&π‘Ž_12@π‘Ž_21&π‘Ž_22 )] B = [β– 8(3&2@1&4@5&3)] B = [β– 8(3&2@1&4@5&3)]_(3 Γ— 2) Matrix Order [β– 8(9&5&2@1&8&5@3&1&6)] 3 Γ— 3 [β– 8(1&2&5&8&π‘₯&𝑧)] 1 Γ— 6 [β– 8(5@9@3@𝑦@tan^(βˆ’1)⁑π‘₯ )] 5 Γ— 1 [β– 8(sin⁑π‘₯&cos⁑π‘₯&tan⁑π‘₯&cot⁑π‘₯@sin⁑𝑦&cos⁑𝑦&tan⁑𝑦&cot⁑𝑦@sin⁑𝑧&cos⁑𝑧&tan⁑𝑧&cot⁑𝑧 )] 3 Γ— 4 A = [β– 8(π‘Ž_11&π‘Ž_12&π‘Ž_13@π‘Ž_21&π‘Ž_22&π‘Ž_23@π‘Ž_31&π‘Ž_32&π‘Ž_33@π‘Ž_41&π‘Ž_42&π‘Ž_43 )] A = [β– 8(2&3&4@3&4&5@4&5&6@5&6&7)] A = [β– 8(2&3&4@3&4&5@4&5&6@5&6&7)]

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.