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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.2, 4 Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (i) 5๐‘Ž, 3๐‘Ž^2, 7๐‘Ž^4 Length = 5๐‘Ž , Breadth = ใ€–3๐‘Žใ€—^2, Height = ใ€–7๐‘Žใ€—^4 Volume = Length ร— Breadth ร— Height = 5๐‘Ž ร— ใ€–3๐‘Žใ€—^2 ร— ใ€–7๐‘Žใ€—^4 = 5 ร— ๐‘Ž ร— 3 ร— ๐‘Ž^2 ร— 7 ร— ๐‘Ž^4 = (5ร—3ร—7) ร— (๐‘Žร—๐‘Ž^2ร—๐‘Ž^4 ) = 105 ร— ๐‘Ž^(1 + 2 + 4) = ๐Ÿ๐ŸŽ๐Ÿ“๐’‚^๐Ÿ• Ex 9.2, 4 Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (ii) 2๐‘, 4๐‘ž, 8๐‘Ÿ Length = 2๐‘, Breadth = 4๐‘ž, Height = 8๐‘Ÿ Volume = Length ร— Breadth ร— Height = 2๐‘ ร— 4๐‘ž ร— 8๐‘Ÿ = 2 ร— ๐‘ ร— 4 ร— ๐‘ž ร— 8 ร— ๐‘Ÿ = (2ร—4ร—8) ร— (๐‘ร—๐‘žร—๐‘Ÿ) = 64 ร— ๐‘๐‘ž๐‘Ÿ = ๐Ÿ”๐Ÿ’๐’‘๐’’๐’“ Ex 9.2, 4 Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (iii) ๐‘ฅ๐‘ฆ, 2๐‘ฅ^2 ๐‘ฆ, 2๐‘ฅ๐‘ฆ^2 Length = ๐‘ฅ๐‘ฆ, Breadth = 2๐‘ฅ^2 ๐‘ฆ, Height = 2๐‘ฅ๐‘ฆ^2 Volume = Length ร— Breadth ร— Height = ๐‘ฅ๐‘ฆ ร— 2๐‘ฅ^2 ๐‘ฆ ร— 2๐‘ฅ๐‘ฆ^2 = ๐‘ฅ ร— ๐‘ฆ ร— 2 ร— ๐‘ฅ^2 ร— ๐‘ฆ ร— 2 ร— ๐‘ฅ ร— ๐‘ฆ^2 = (2ร—2) ร— (๐‘ฅร—๐‘ฅ^2ร—๐‘ฅ) ร— (๐‘ฆร—๐‘ฆร—๐‘ฆ^2 ) = 4 ร— ๐‘ฅ^4 ร— ๐‘ฆ^4 = ๐Ÿ’๐’™^๐Ÿ’ ๐’š^๐Ÿ’ Ex 9.2, 4 Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (iv) ๐‘Ž, 2๐‘, 3๐‘ Length = ๐‘Ž, Breadth = 2๐‘, Height = 3๐‘ Volume = Length ร— Breadth ร— Height = ๐‘Ž ร— 2๐‘ ร— 3๐‘ = ๐‘Ž ร— 2 ร— ๐‘ ร— 3 ร— ๐‘ = (2ร—3) ร— (๐‘Žร—๐‘ร—๐‘) = 6 ร— ๐‘Ž๐‘๐‘ = ๐Ÿ”๐’‚๐’ƒ๐’„

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.