Last updated at April 16, 2024 by Teachoo
Ex 8.2, 5 Obtain the product of (iii) 2, 4𝑦, 8𝑦^2, 16𝑦^3 2" ×" 4𝑦" ×" 8𝑦^2 " ×" 16𝑦^3 = 2 × 4𝑦 × 8𝑦^2 × 16𝑦^3 = 2 × 4 × 𝑦 × 8 × 𝑦^2 × 16 × 𝑦^3 = (𝟐 × 𝟒 × 𝟖 × 𝟏𝟔) × (𝒚 × 𝒚^𝟐 × 𝒚^𝟑 ) = 1024 × 𝑦^(1 + 2 + 3) = 1024 × 𝑦^6 = 𝟏𝟎𝟐𝟒𝒚^𝟔