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Ex 9.2, 8 - Chapter 9 Class 7 Perimeter and Area
Last updated at July 4, 2023 by Teachoo
Ex 9.2
Ex 9.2, 1 (a)
Ex 9.2, 1 (b) Important
Ex 9.2, 1 (c)
Ex 9.2, 2 (a) Important
Ex 9.2, 2 (b) Important
Ex 9.2, 2 (c)
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Ex 9.2, 4 Important
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Ex 9.2, 8 You are here
Ex 9.2, 9 Important
Ex 9.2, 10 Important
Ex 9.2, 11
Ex 9.2, 12 Important
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Ex 9.2, 14
Ex 9.2, 15
Ex 9.2, 16 Important
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Transcript
Ex 9.2, 8 Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is Rs 15/m2. (Take π = 3.14) Here, Area to be polished = Area of circular table top Diameter = 1.6 m Radius = r = 𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟/2 = (𝟏.𝟔)/𝟐 = 16/(2 × 10) Area of table top = 𝜋r2 = 3.14 × (𝟖/𝟏𝟎)^𝟐 = 314/100 × 8/10 × 8/10 = (𝟑𝟏𝟒 × 𝟔𝟒)/𝟏𝟎𝟎𝟎𝟎 = 20096/10000 = 2.0096 m2 Now, Cost of polishing 1 m2 area = Rs 15 Cost of polishing 2.0096 m2 area = Rs 15 × 2.0096 = Rs 15 × 𝟐𝟎𝟎𝟗𝟔/𝟏𝟎𝟎𝟎𝟎 = Rs 3 × 20096/2000 = Rs 3 × 𝟏𝟎𝟎𝟒𝟖/𝟏𝟎𝟎𝟎 = Rs 30144/1000 = Rs 30.144 = Rs 30.14 (approx.) ∴ It will cost Rs 30.14 (approx.) to polish the table top
