

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 9.2
Ex 9.2, 1 (b) Important
Ex 9.2, 1 (c)
Ex 9.2, 2 (a) Important
Ex 9.2, 2 (b) Important
Ex 9.2, 2 (c)
Ex 9.2, 3
Ex 9.2, 4 Important
Ex 9.2, 5 Important
Ex 9.2, 6 You are here
Ex 9.2, 7 Important
Ex 9.2, 8
Ex 9.2, 9 Important
Ex 9.2, 10 Important
Ex 9.2, 11
Ex 9.2, 12 Important
Ex 9.2, 13 Important
Ex 9.2, 14
Ex 9.2, 15
Ex 9.2, 16 Important
Ex 9.2, 17 Important
Last updated at July 4, 2023 by Teachoo
Ex 9.2, 6 Saima wants to put a lace on the edge of a circular table cover of diameter 1.5 m. Find the length of the lace required and also find its cost if one meter of the lace costs Rs 15. (Take π = 3.14) Here, Length of lace = Circumference of table Given Diameter = 1.5 cm Radius = r = 𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟/2 = (𝟏.𝟓)/𝟐 = 15/(10 × 2) = 3/(2 × 2) = 𝟑/𝟒 m Circumference of table = 2𝜋r = 2 × 3.14 × 𝟑/𝟒 = 2 × 314/100 × 3/4 = 𝟑/𝟐 × 𝟑𝟏𝟒/𝟏𝟎𝟎 = 3 × 157/100 = 471/100 = 4.71 m So, length of lace required is 4.71 cm Now, we have to find cost Now, Cost of 1 m lace = Rs 15 Cost of 4.71 m lace = Rs 15 × 4.71 = Rs 15 × 𝟒𝟕𝟏/𝟏𝟎𝟎 = Rs 7065/100 = Rs 70.65 Cost of lace required is Rs 70.65 So, length of lace required is 4.71 cm Now, we have to find cost Now, Cost of 1 m lace = Rs 15 Cost of 4.71 m lace = Rs 15 × 4.71 = Rs 15 × 𝟒𝟕𝟏/𝟏𝟎𝟎 = Rs 7065/100 = Rs 70.65 Cost of lace required is Rs 70.65