1. Chapter 11 Class 7 Perimeter and Area
  2. Serial order wise
  3. Ex 11.3

Ex 11.3, 2 (b) - Chapter 11 Class 7 Perimeter and Area

Last updated at Oct. 25, 2021 by

Ex 11.3, 2 - Chapter 11 Class 7 Perimeter and Area - Part 2

Ex 11.3, 2 - Chapter 11 Class 7 Perimeter and Area - Part 3

  1. Chapter 11 Class 7 Perimeter and Area
  2. Serial order wise

    3. Ex 11.3

    Ex 11.4ย โ†’

Transcript

Ex 11.3, 2 Find the area of the following circles, given that: (b) diameter = 49 m Diameter = 21 cm Radius = r = ๐ท๐‘–๐‘Ž๐‘š๐‘’๐‘ก๐‘’๐‘Ÿ/2 = 49/2 m Now, Area of circle = ๐œ‹ r2 = 22/7 ร— (49/2)^2 = 22/7 ร— 49/2 ร— 49/2 = 11/7 ร— 49/1 ร— 49/2 = 11/1 ร— 7 ร— 49/2 = (77 ร— 49)/2 = 3773/2 = 1886.5 m2 โˆด Required area is 1886.5 m2

Chapter 11 Class 7 Perimeter and Area
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.