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  1. Chapter 11 Class 7 Perimeter and Area
  2. Serial order wise

Transcript

Ex 11.2, 8 ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of Δ ABC. What will be the height from C to AB i.e., CE? Finding area of ∆ABC Using BC as base and AD as height Here, Base = BC = 9 cm Height = AD = 6 cm Area of ∆ABC = 1/2 × Base × Height = 1/2 × BC × AD = 1/2 × 9 × 6 = 9 × 3 = 27 cm2 Now, we have to find EC which is height corresponding to base AB So, finding Area using EC as height and AB as base Base = AB = 7.5 cm Height = EC = ? Area of ∆ABC = 1/2 × Base × Height 27 = 1/2 × 7.5 × EC (27 × 2)/7.5 = EC (27 × 2 × 10)/75 = EC (9 × 2 × 10)/25 = EC (9 × 2 × 2)/5 = EC 36/5 = EC 7.2 = EC EC = 7.2 cm ∴ Area of ∆ABC is 27 cm2 and Height CE is 7.2 cm

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.