Ex 9.1, 3 - Find the missing values - Base | Height | Area of - Ex 9.1

part 2 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area

  

part 3 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area

part 4 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area

 

part 5 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area part 6 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area

part 7 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area part 8 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area part 9 - Ex 9.1, 3 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area

 

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Transcript

Ex 9.1, 3 Find the missing values: Base = 20 cm, Height = ?, Area = 246 cm2 Base = b = 20 cm Height = h Area of parallelogram = b × h 246 = 20 × h 𝟐𝟒𝟔/𝟐𝟎 = h 123/10 = h 12.3 = h h = 12.3 cm ∴ Height = 12.3 cm (b) Base = ?, Height = 15 cm, Area = 154.5 cm2 Base = b Height = h = 15 cm Area of parallelogram = b × h 154.5 = b × 15 154.5/15 = b b = (𝟏𝟓𝟒.𝟓)/𝟏𝟓 b = 1545/15 × 1/10 b = 𝟑𝟎𝟗/𝟑 × 𝟏/𝟏𝟎 b = 103 × 1/10 b = 10.3 cm ∴ Base = 10.3 cm (c) Base = ?, Height = 8.4 cm, Area = 48.72 cm2 Base = b Height = h = 8.4 cm Area of parallelogram = b × h 48.72 = b × 8.4 48.72/8.4 = b b = 48.72 × 𝟏/(𝟖.𝟒) b = 4872/100 × 10/84 b = 4872/10 × 1/84 b = 𝟒𝟖𝟕𝟐/𝟖𝟒 × 𝟏/𝟏𝟎 b = 1281/21 × 1/10 b = 406/7 × 1/10 b = 58 × 1/10 b = 5.8 cm ∴ Base = 5.8 cm (d) Base = 15.6 cm, Height = ?, Area = 16.38 cm2 Base = b = 15.6 cm Height = h Area of parallelogram = b × h 16.38 = 15.6 h 16.38/15.6 = h h = (𝟏𝟔.𝟑𝟖)/(𝟏𝟓.𝟔) h = 16.38 × 1/15.6 h = 𝟏𝟔𝟑𝟖/𝟏𝟎𝟎 × 𝟏𝟎/𝟏𝟓𝟔 h = 1638/10 × 1/156 h = 𝟏𝟔𝟑𝟖/𝟏𝟓𝟔 × 𝟏/𝟏𝟎 h = 819/78 × 1/10 h = 273/26 × 1/10 h = 𝟐𝟏/𝟐 × 𝟏/𝟏𝟎 h = 10.5 × 1/10 h = 1.05 ∴ Height = 1.05 cm

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo