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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 9.1, 5 PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR & QN is the height from Q to PS. If SR = 12 cm & QM = 7.6 cm. Find: (a) the area of the parallelogram PQRS (b) QN, if PS = 8 cm Finding area of parallelogram Using QM as height and SR as base Here, Base = SR = 12 cm Height = QM = 7.6 cm Area of parallelogram = Base × Height = SR × QM = 12 × 7.6 = 12 × 76/10 = 912/10 = 91.2 cm2 Now, we have to find QN, if PS = 8 cm Our figure looks like So, Base = PS = 8 cm Height = QN = ? Area of parallelogram = Base × height 91.2 = PS × QN 91.2 = 8 × QN (𝟗𝟏.𝟐)/𝟖 = QN 912/(8 × 10) = QN 114/10 = QN 11.4 = QN QN = 11.4 cm Therefore, Area of parallelogram is 91.2 cm2 & Length of QN is 11.4 cm

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.