Ex 9.1, 6 - DL and BM are the heights on sides AB and AD of - Ex 9.1

part 2 - Ex 9.1, 6 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area

part 3 - Ex 9.1, 6 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area part 4 - Ex 9.1, 6 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area part 5 - Ex 9.1, 6 - Ex 9.1 - Serial order wise - Chapter 9 Class 7 Perimeter and Area

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Ex 9.1, 6 DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (Fig 11.24). If the area of the parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL. Here, We can find area of parallelogram using: AB as base & DL as height Or AD as base & BM as height Given, Area = 1470 cm2 Base = AB = 35 cm Height = DL = ? Area of parallelogram = Base × Height 1470 = AB × DL 1470 = 35 × DL 1470/35 = DL 210/5 = DL 42 = DL DL = 42 cm Given, Area = 1470 cm2 Base = AB = 35 cm Height = DL = ? Area of parallelogram = Base × Height 1470 = AB × DL 1470 = 35 × DL Given, Area = 1470 cm2 Base = AD = 35 cm Height = BM = ? Area of parallelogram = Base × Height 1470 = AD × BM 1470 = 49 × BM 𝟏𝟒𝟕𝟎/𝟑𝟓 = DL 210/5 = DL 42 = DL DL = 42 cm 𝟏𝟒𝟕𝟎/𝟒𝟗 = BM 210/7 = BM 30 = BM BM = 30 cm Therefore, Length of DL is 42 cm and Length of BM is 30 cm

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