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Ex 9.1, 6 - Chapter 9 Class 7 Perimeter and Area
Last updated at May 18, 2023 by Teachoo
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
-
Area of parallelogram
- Area of triangle
- Circumference of circle
- Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Ex 9.1, 6 DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (Fig 11.24). If the area of the parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL. Here, We can find area of parallelogram using: AB as base & DL as height Or AD as base & BM as height Given, Area = 1470 cm2 Base = AB = 35 cm Height = DL = ? Area of parallelogram = Base × Height 1470 = AB × DL 1470 = 35 × DL 1470/35 = DL 210/5 = DL 42 = DL DL = 42 cm 1470/35 = DL 210/5 = DL 42 = DL DL = 42 cm Given, Area = 1470 cm2 Base = AB = 35 cm Height = DL = ? Area of parallelogram = Base × Height 1470 = AB × DL 1470 = 35 × DL Using AD & BM Given, Area = 1470 cm2 Base = AD = 35 cm Height = BM = ? Area of parallelogram = Base × Height 1470 = AD × BM 1470 = 49 × BM 1470/35 = DL 210/5 = DL 42 = DL DL = 42 cm 1470/49 = BM 210/7 = BM 30 = BM BM = 30 cm ∴ Length of DL is 42 cm and Length of BM is 30 cm
