Let’s take a rectangle

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And add a semicircle on top of side CD & AB

Area of combination of figures - Part 2

 

What will be the area of total figure?

Area of combination of figures - Part 3

 

Area of total figure = Area of rectangle + Area of top semicircle + Area of bottom semicircle.

 

So, area gets added

 

Let’s take some values & actually solve it

 

What will be the area of the figure given below?

Area of combination of figures - Part 4

 

Here,

Area of total Figure =  Area of rectangle  + Area of top semicircle + Area of bottom semicircle

 

Here, Both semicircle will have the same diameter,

So, their area will be the same

 

∴ Area of total figure = Area of rectangle + 2 × Area of semicircle

Let’s find them out separately

 

Area of rectangle

Area of combination of figures - Part 5

 

Length = l = AB

      = 20 cm

 

Breadth = b = BC

      = 5 cm

 

Area of rectangle ABCD = l × b

     = AB × BC

     = 20 × 5

     = 100 cm 2

 

Area of semi-circle

Area of combination of figures - Part 6

Diameter = 20 cm

 

   Radius = r = Diameter/2

        = 20/2

= 10 cm

 

Now,

  Area of semi-circle = (Area of circle)/2

  = πr 2 /2

  = (3.14  (10) 2 )/2

  = (314 × 100)/(100 × 2)

  = 314/2

  = 157 cm 2

Now,

  Area of figure = Area of rectangle ABCD + 2 Area of semi-circle

 = 100 + 2 × (157)

 = 100 + 314

 = 414 cm 2

∴ Area of given figure is 514 cm 2

 

 

 

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.