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Ex 11.2, 3 - Find the missing values - Base | Height | Area of

Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 2
Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 3 Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 4 Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 5 Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 6 Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 7 Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 8 Ex 11.2, 3 - Chapter 11 Class 7 Perimeter and Area - Part 9

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Ex 9.1, 3 Find the missing values: Base = 20 cm, Height = ?, Area = 246 cm2 Base = b = 20 cm Height = h Area of parallelogram = b × h 246 = 20 × h 246/20 = h 123/10 = h 12.3 = h h = 12.3 cm ∴ Height = 12.3 cm (b) Base = ?, Height = 15 cm, Area = 154.5 cm2 Base = b Height = h = 15 cm Area of parallelogram = b × h 154.5 = b × 15 154.5/15 = b b = 154.5/15 b = 1545/15 × 1/10 b = 309/3 × 1/10 b = 103 × 1/10 b = 10.3 cm ∴ Base = 10.3 cm (c) Base = ?, Height = 8.4 cm, Area = 48.72 cm2 Base = b Height = h = 8.4 cm Area of parallelogram = b × h 48.72 = b × 8.4 48.72/8.4 = b b = 48.72 × 1/8.4 b = 4872/100 × 10/84 b = 4872/10 × 1/84 b = 4872/84 × 1/10 b = 1281/21 × 1/10 b = 406/7 × 1/10 b = 58 × 1/10 b = 5.8 cm ∴ Base = 5.8 cm (d) Base = 15.6 cm, Height = ?, Area = 16.38 cm2 Base = b = 15.6 cm Height = h Area of parallelogram = b × h 16.38 = 15.6 h 16.38/15.6 = h h = 16.38/15.6 h = 16.38 × 1/15.6 h = 1638/100 × 10/156 h = 1638/10 × 1/156 h = 1638/156 × 1/10 h = 819/78 × 1/10 h = 273/26 × 1/10 h = 21/2 × 1/10 h = 10.5 × 1/10 h = 1.05 ∴ Height = 1.05 cm

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.