Slide28.JPG

Slide29.JPG

Slide30.JPG
Slide31.JPG

Go Ad-free

Transcript

Ex 9.1, 5 PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR & QN is the height from Q to PS. If SR = 12 cm & QM = 7.6 cm. Find: (a) the area of the parallelogram PQRS (b) QN, if PS = 8 cm Finding area of parallelogram Using QM as height and SR as base Here, Base = SR = 12 cm Height = QM = 7.6 cm Area of parallelogram = Base × Height = SR × QM = 12 × 7.6 = 12 × 76/10 = 912/10 = 91.2 cm2 Now, we have to find QN, if PS = 8 cm Our figure looks like So, Base = PS = 8 cm Height = QN = ? Area of parallelogram = Base × height 91.2 = PS × QN 91.2 = 8 × QN (𝟗𝟏.𝟐)/𝟖 = QN 912/(8 × 10) = QN 114/10 = QN 11.4 = QN QN = 11.4 cm Therefore, Area of parallelogram is 91.2 cm2 & Length of QN is 11.4 cm

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.