1. Chapter 10 Class 6 Mensuration
2. Concept wise
3. Area of Rectangle

Transcript

Example 16 Bob wants to cover the floor of a room 3 m wide and 4 m long by squared tiles. If each square tile is of side 0.5 m, then find the number of tiles required to cover the floor of the room. Here, Number of tiles = (๐๐๐ก๐๐ ๐๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐)/(๐ด๐๐๐ ๐๐๐ ๐๐ข๐๐๐ ๐ก๐๐๐) Finding area of rectangular room and square tile Rectangular room Length of rectangular room = l = 4 m Breadth of rectangular room = b = 3 m Area of room = l ร b = 4 ร 3 = 12 sq. m = 12 ๐^2 Square tile Side of square tile = a = 0.5 m Area of tile = a ร a = 0.5 ร 0.5 = 5/10 ร 5/10 = 25/100 sq m2 Now, Number of tiles = (๐๐๐ก๐๐ ๐๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐ก๐๐๐๐  ๐ ๐๐ข๐๐๐) = 12/(25/100) = 12 ร 100/25 = 12 ร 4 = 48 โด 48 tiles are required to cover the room

Area of Rectangle