Let’s take a rectangle

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We know that

In a rectangle, opposite sides are equal

  AB = CD

&  AD = BC

 

Let  

  AB = Length of rectangle = l

  BC = Breadth of rectangle = b

Perimeter of rectangle - Part 2

So,

  AB = CD = l

  BC = AD = b

 

 

Perimeter of rectangle - Part 3

 

Now,

  Perimeter of rectangle = Sum of all sides

= AB + BC + CD + DA

= l + b + l + b

= 2 l + 2b

= 2 ( l + b)

 

So,

     Perimeter of rectangle = 2 ( l + b)

 

Let’s take some examples

 

Find perimeter of rectangle where length is 15cm & breadth is 9 cm

Perimeter of rectangle - Part 4

Given,

  Length = l = 15 cm

  Breadth = b = 9 cm

 

Perimeter of rectangle = 2 × (Length + Breadth)

     = 2 × (15 + 9)

     = 2 × 24

= 48 cm

 

So, perimeter of rectangle is 48 cm

 

Find perimeter of rectangle where length & breadth are 0.5 m & 0.2 m respectively.

Given,

  Length = l = 0.5 cm

  Breadth = b = 0.2 cm

Perimeter of rectangle - Part 5

 

Perimeter of rectangle = 2 × (Length + Breadth)

= 2 × (0.5 + 0.2)

= (2 × 0.7)

= 1.4 m

= 1.4 × 100 cm               (1m = 100 cm)

= 140 cm

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.