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Ex 10.1, 2 - Chapter 10 Class 6 Mensuration
Last updated at July 20, 2026 by Teachoo
Chapter 10 Class 6 Mensuration
Concept wise
- Perimeter
-
Perimeter of Rectangle
- Perimeter of Square
- Perimeter of Triangle
- Perimeter of Pentagon and Hexagon
- Area - Definition
- Finding area by counting squares
- Area of Square
- Area of Rectangle
- Area by splitting into rectangles
- Finding Area by Changing units
- Area questions with both rectangles and squares
Transcript
Ex 10.1, 2 The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required? Length = l = 40 cm Breadth = b = 10 cm Length of tape required = Perimeter of rectangle = 2 × (Length + Breadth) = 2 × (40 + 10) = 2 × (50) = 100 cm = 1 m (1m = 100 cm) ∴ 1m of tape is required for sealing rectangular box
