# Ex 10.3, 12 - Chapter 10 Class 6 Mensuration

Last updated at Nov. 15, 2018 by Teachoo

Last updated at Nov. 15, 2018 by Teachoo

Transcript

Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (a) 100 cm and 144 cm Here, Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐) Finding area of rectangular region and rectangular tile Rectangular tile Length of tile = 12 cm Breadth of tile = 5 cm Area of tile = Length ร Breadth = 12 ร 5 = 60 sq. cm = 60 cm2 Rectangular region Length of region = 100 cm Breadth of region = 144cm Area of region = Length ร Breadth = 100 ร 144 = 14400 sq. cm = 14400 cm2 Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐๐ ) = 14400/60 = 1440/6 = 240 โด 240 tiles are required to cover the region Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (b) 70 cm and 36 cm. Here, Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐) From part (a), Area of rectangular tile = 60 cm2 Finding area of rectangular region Rectangular region Length of rectangle = 70 cm Breadth of rectangle = 36 cm Area of rectangle = Length ร Breadth = 70 ร 36 = 2520 sq. cm = 2520 ใ๐๐ใ^2 Now, Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐๐ ) = 2520/60 = 252/6 = 42 โด 42 tiles are required to cover the given region

Chapter 10 Class 6 Mensuration

Concept wise

- Perimeter
- Perimeter of Rectangle
- Perimeter of Square
- Perimeter of Triangle
- Perimeter of Pentagon and Hexagon
- Area - Definition
- Finding area by counting squares
- Area of Square
- Area of Rectangle
- Area by splitting into rectangles
- Finding Area by Changing units
- Area questions with both rectangles and squares

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.