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Ex 8.2, 7 - A milkman sold two of his buffaloes for Rs 20,000 each

Ex 8.2, 7 - Chapter 8 Class 8 Comparing Quantities - Part 2
Ex 8.2, 7 - Chapter 8 Class 8 Comparing Quantities - Part 3 Ex 8.2, 7 - Chapter 8 Class 8 Comparing Quantities - Part 4 Ex 8.2, 7 - Chapter 8 Class 8 Comparing Quantities - Part 5 Ex 8.2, 7 - Chapter 8 Class 8 Comparing Quantities - Part 6 Ex 8.2, 7 - Chapter 8 Class 8 Comparing Quantities - Part 7

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Question 6 A milkman sold two of his buffaloes for Rs 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each) Given, Selling Price of buffalos = 20000 each Total Selling price (SP) = 2 Γ— Selling price of 1 buffalo = 2 Γ— 20000 = 40000 Total Cost Price (CP) = Cost Price of first buffalo + Cost price of Second buffalo Cost Price of first Buffalo Selling Price = 20000 Gain Percentage = 5% Let the cost Price = π‘₯ We know that, Gain = Selling Price βˆ’ Cost Price Gain = 20000 βˆ’ π‘₯ Also, Gain Percentage = πΊπ‘Žπ‘–π‘›/(πΆπ‘œπ‘ π‘‘ π‘ƒπ‘Ÿπ‘–π‘π‘’) Γ— 100 5 = (20000 βˆ’ π‘₯)/π‘₯ Γ— 100 5π‘₯ = (20000 βˆ’ x) Γ— 100 5π‘₯ = 200000 βˆ’ 100x 5x + 100π‘₯ = 2000000 105π‘₯ = 2000000 x = 2000000/105 Cost Price of first Buffalo Selling Price = 20000 Gain Percentage = 5% Let the cost Price = π‘₯ We know that, Gain = Selling Price βˆ’ Cost Price Gain = 20000 βˆ’ π‘₯ Also, Gain Percentage = πΊπ‘Žπ‘–π‘›/(πΆπ‘œπ‘ π‘‘ π‘ƒπ‘Ÿπ‘–π‘π‘’) Γ— 100 5 = (20000 βˆ’π‘₯)/π‘₯ Γ— 100 Cost Price of second Buffalo Selling Price = 20000 Loss Percentage = 10% Let the cost Price = y We know that, Loss = Cost Price βˆ’ Selling Price Loss = y βˆ’ 20000 Also, Loss Percentage = πΏπ‘œπ‘ π‘ /(πΆπ‘œπ‘ π‘‘ π‘ƒπ‘Ÿπ‘–π‘π‘’) Γ— 100 10 = (𝑦 βˆ’ 20000)/𝑦 Γ— 100 5π‘₯ = (20000 βˆ’ x) Γ— 100 5π‘₯ = 200000 βˆ’ 100x 5x + 100π‘₯ = 2000000 105π‘₯ = 2000000 x = 2000000/105 10y = (y βˆ’ 20000) Γ— 100 10y = 100y βˆ’ 2000000 10y – 100y = βˆ’2000000 βˆ’ 90y = βˆ’2000000 90y = 2000000 y = 2000000/90 ∴ Cost Price of first buffalo = Rs 2000000/105 & Cost Price of Second buffalo = Rs 2000000/90 Putting values in equation (1) Total Cost Price (CP) = Cost Price of first buffalo + Cost Price of Second Buffalo = 2000000/90 + 2000000/105 = 2000000 (1/90 " + " 1/105) = 2000000 ((105 + 90)/(105 Γ— 9)) = 2000000 (195/(105 Γ— 90)) = 200000 (195/(105 Γ— 9)) = 200000 (65/(105 Γ— 3)) = 200000 (13/(21 Γ— 3)) = 2600000/63 = 41269.83 ∴ SP = Rs 40,000 & CP = Rs 41,269.83 Since CP > SP, He Made a loss Loss = CP βˆ’ SP = 41269.83 βˆ’ 40000 = 1269.83 ∴ His overall loss is of Rs 1,269.83

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.