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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Transcript

Ex 8.2, 4 The cost of an article was Rs 15,500. Rs 450 were spent on its repairs. If it is sold for a profit of 15%, find the selling price of the article. Given, Cost Price of an article = 15500 Money spent on Repairs = 450 Profit Percentage = 15% Now, Total Cost price will cost price of article + Money spent on repairs Total Cost Price (CP) = Cost Price of article + Money spent on repairs = 15500 + 450 = 15950 Now, Profit Percentage = π‘ƒπ‘Ÿπ‘œπ‘“π‘–π‘‘/𝐢𝑃 Γ— 100 15 = π‘ƒπ‘Ÿπ‘œπ‘“π‘–π‘‘/15950Γ—100 (15 Γ— 15950)/100 = Profit (15 Γ— 1595)/10 = Profit 23925/10 = Profit 2392.5 = Profit ∴ Profit = 2392.5 Now, Profit = SP βˆ’ CP 2392.5 = SP βˆ’ 15950 2392.5 + 15950 = SP 1834.5 = SP ∴ SP = 18342.5 ∴ Selling Price of the article = Rs 18,342.50

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.