# Ex 8.3, 11 - Chapter 8 Class 7 Comparing Quantities

Last updated at Nov. 6, 2018 by Teachoo

Ex 8.3

Ex 8.3, 1 (a)

Ex 8.3, 1 (b) Important

Ex 8.3, 1 (c)

Ex 8.3, 1 (d) Important

Ex 8.3, 2 (a)

Ex 8.3, 2 (b) Important

Ex 8.3, 2 (c) Important

Ex 8.3, 2 (d)

Ex 8.3, 3

Ex 8.3, 4 Important

Ex 8.3, 5

Ex 8.3, 6 Important

Ex 8.3, 7 Important

Ex 8.3, 8

Ex 8.3, 9 (a) Important

Ex 8.3, 9 (b)

Ex 8.3, 10

Ex 8.3, 11 Important You are here

Last updated at Nov. 6, 2018 by Teachoo

Ex 8.3, 11 If Meena gives an interest of Rs 45 for one year at 9% rate p.a. What is the sum she has borrowed? I = Rs 45 T = 1 year R = 9% p.a P = ? Now, I = ππ π/100 45 = (π Γ 9 Γ 1)/100 45 Γ 100 = 9P 9P = 45 Γ 100 9P = 4500 P = 4500/9 P = Rs 500 So, she has borrowed Rs 500