Misc 3 - Practical Geometry

Last updated at April 16, 2024 by

Misc 3 - Construct ABC - A = 70; B = 50; AC = 3 cm - Chapter 10

Misc 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Misc 3 - Chapter 10 Class 7 Practical Geometry - Part 3
Misc 3 - Chapter 10 Class 7 Practical Geometry - Part 4
Misc 3 - Chapter 10 Class 7 Practical Geometry - Part 5 Misc 3 - Chapter 10 Class 7 Practical Geometry - Part 6

Transcript

Misc 3 Below are given the measures of certain sides and angles of triangles. Identify those which cannot be constructed and, say why you cannot construct them. Construct rest of the triangles. Here, ∠ A + ∠ B = 70° + 50° = 110° < 180° So, Δ ABC is possible But, to construct it, We need to find ∠ Finding ∠ C In Δ ABC, Sum of angles = 180° ∠ A + ∠ B + ∠ C = 180° 70° + 50° + ∠ C = 180° 120° + ∠ C = 180° ∠ C = 180° – 110° ∠ C = 60° Now, let’s construct it Steps of construction 1. Draw a line segment AC of length 3 cm 2. Now, we draw 70° from point A (using protractor) 3. Now, we draw 60° from point C Check Construction 11.3 of Chapter 11 Class 9 NCERT to see how to draw 60° 4. Let point B be the point where the two rays intersect and label the sides Thus, Δ ABC is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.