Subscribe to our Youtube Channel - https://you.tube/teachoo

Last updated at Oct. 1, 2018 by Teachoo

Transcript

Example 2 Construct a triangle PQR, given that PQ = 3 cm, QR = 5.5 cm and ∠PQR = 60°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment QR of length 5.5 cm 2. Now, we draw 60° from point Q Check Construction 11.3 of Chapter 11 Class 9 NCERT to see how to draw 60° 3. Taking Q as center, 3 cm as radius, we draw an arc Let the point where arc intersects the ray be point P 4. Join PR and label the sides Thus, Δ PQR is the required triangle

Constructing a triangle when 2 sides and angle between is known (SAS)

Chapter 10 Class 7 Practical Geometry

Concept wise

- Construction of line parallel to given line, through point not on line
- Constructing a triangle when 3 sides known (SSS)
- Constructing a triangle when 2 sides and angle between is known (SAS)
- Constructing a triangle when 2 angles and side between is known (ASA)
- Constructing a right triangle when hypotenuse and side is given (RHS)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.