Example 2 - Practical Geometry

Last updated at July 27, 2026 by

Example 2 - Construct triangle PQR, given PQ = 3 cm, QR = 5.5 cm, PQR

Example 2 - Chapter 10 Class 7 Practical Geometry - Part 2
Example 2 - Chapter 10 Class 7 Practical Geometry - Part 3 Example 2 - Chapter 10 Class 7 Practical Geometry - Part 4 Example 2 - Chapter 10 Class 7 Practical Geometry - Part 5

Remove Ads

Transcript

Example 2 Construct a triangle PQR, given that PQ = 3 cm, QR = 5.5 cm and ∠PQR = 60°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment QR of length 5.5 cm 2. Now, we draw 60° from point Q Check Construction 11.3 of Chapter 11 Class 9 NCERT to see how to draw 60° 3. Taking Q as center, 3 cm as radius, we draw an arc Let the point where arc intersects the ray be point P 4. Join PR and label the sides Thus, Δ PQR is the required triangle

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.