Question 3 - Constructing a triangle when 2 sides and angle between is known (SAS) - Practical Geometry

Last updated at July 27, 2026 by

Ex 10.3, 3 - Construct ABC with BC = 7.5 cm, AC = 5 cm and C = 60

Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 3 Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 4 Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 5

Remove Ads

Transcript

Question 3 Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment CB of length 7.5 cm 2. Now, we draw 60° from point C 3. Taking C as center, 5 cm as radius, we draw an arc Let the point where arc intersects the ray be point A 4. Join AB and label the sides Thus, Δ ABC is the required triangle

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.