# Ex 10.3, 1 - Chapter 10 Class 7 Practical Geometry

Last updated at Oct. 1, 2018 by Teachoo

Last updated at Oct. 1, 2018 by Teachoo

Transcript

Ex 10.3, 1 Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°. First we draw a rough sketch To construct it, We follow these steps Steps of construction 1. Draw a line segment DF of length 3 cm 2. Now, we draw 90° from point D Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Taking D as center, 5 cm as radius, we draw an arc Let the point where arc intersects the ray be point E 4. Join EF and label the sides Thus, Δ DEF is the required triangle

Constructing a triangle when 2 sides and angle between is known (SAS)

Chapter 10 Class 7 Practical Geometry

Concept wise

- Construction of line parallel to given line, through point not on line
- Constructing a triangle when 3 sides known (SSS)
- Constructing a triangle when 2 sides and angle between is known (SAS)
- Constructing a triangle when 2 angles and side between is known (ASA)
- Constructing a right triangle when hypotenuse and side is given (RHS)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.