![Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 2](https://d1avenlh0i1xmr.cloudfront.net/5317e9de-d816-4cfd-9a56-c80b35a7eb24/slide12.jpg)
![Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 3](https://d1avenlh0i1xmr.cloudfront.net/0d919398-52ee-4a2f-a995-691ad144c46e/slide13.jpg)
![Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 4](https://d1avenlh0i1xmr.cloudfront.net/3b32c249-1fc4-444c-99d0-bb54084a72a9/slide14.jpg)
![Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 5](https://d1avenlh0i1xmr.cloudfront.net/a9646110-ef06-47be-9ea4-1c458bceb340/slide15.jpg)
Constructing a triangle using SAS congruency criteria
Constructing a triangle using SAS congruency criteria
Last updated at April 16, 2024 by Teachoo
Question 3 Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment CB of length 7.5 cm 2. Now, we draw 60° from point C 3. Taking C as center, 5 cm as radius, we draw an arc Let the point where arc intersects the ray be point A 4. Join AB and label the sides Thus, Δ ABC is the required triangle