Check sibling questions

Ex 10.3

Ex 10.4 →
Chapter 10 Class 7 Practical Geometry
Serial order wise

Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry

Last updated at March 23, 2023 by

Ex 10.3, 3 - Construct ABC with BC = 7.5 cm, AC = 5 cm and C = 60

Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 3 Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 4 Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 5

This video is only available for Teachoo black users

Subscribe Now

Get live Maths 1-on-1 Classs - Class 6 to 12

Book 30 minute class for ₹ 499 ₹ 299

Transcript

Ex 10.3, 3 Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment CB of length 7.5 cm 2. Now, we draw 60° from point C 3. Taking C as center, 5 cm as radius, we draw an arc Let the point where arc intersects the ray be point A 4. Join AB and label the sides Thus, Δ ABC is the required triangle

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.