Ex 10.2, 4 - Construct ABC such that AB = 2.5 cm, BC = 6 cm, AC = 6.5

Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 3
Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 4
Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 5

  1. Chapter 10 Class 7 Practical Geometry
  2. Serial order wise

Transcript

Ex 10.2, 4 Construct ∆ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment AB of length 2.5 cm 2. Taking 6.5 cm as radius, and A as center, draw an arc. 3. Taking 6 cm as radius, and B as center, draw another arc. 4. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle On measuring ∠ B, we see that ∠ B = 90°

Chapter 10 Class 7 Practical Geometry
Serial order wise

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