Ex 14.5, 9 Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of (𝑂𝐴) ̅ and (𝑂𝐵) ̅. Let them meet at P. Is PA = PB
Let us consider an angle with vertex O
and points A & B such that
OA = OB
We need to draw perpendicular bisectors of OA and OB.
Drawing perpendicular bisector of OA
We follow these steps
1. With O as center, and radius more than half OA,
draw an arc on top and bottom of OA
With A as center and same radius as before,
draw an arc on top and bottom of OA
2. Where the two arcs intersect above OA is point X
and where the two arcs intersect below OA is point Y
Join XY
Thus, XY is the perpendicular bisector of OA
Now, we draw perpendicular bisector of OB
Drawing perpendicular bisector of OB
We follow these steps
1. With O as center, and radius more than half OB,
draw an arc on top and bottom of OB
With B as center and same radius as before,
draw an arc on top and bottom of OB
2. Where the two arcs intersect above OB is point M
and where the two arcs intersect below OB is point N
Join MN
Thus, MN is the perpendicular bisector of OB
Now,
Point where XY and MN meet is point P
We need to check if PA = PB
Joining PA and PB
Checking length of PA and PB by compass,
We note that their lengths are equal
∴ PA = PB

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

Hi, it looks like you're using AdBlock :(

Displaying ads are our only source of revenue. To help Teachoo create more content, and view the ad-free version of Teachooo... please purchase Teachoo Black subscription.

Please login to view more pages. It's free :)

Teachoo gives you a better experience when you're logged in. Please login :)

Solve all your doubts with Teachoo Black!

Teachoo answers all your questions if you are a Black user!