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Ex 14.5, 9 - Draw any angle with vertex O. Take a point A on one of

Ex 14.5, 9 - Chapter 14 Class 6 Practical Geometry - Part 2
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Ex 14.5, 9 Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of (𝑂𝐴) ̅ and (𝑂𝐵) ̅. Let them meet at P. Is PA = PB Let us consider an angle with vertex O and points A & B such that OA = OB We need to draw perpendicular bisectors of OA and OB. Drawing perpendicular bisector of OA We follow these steps 1. With O as center, and radius more than half OA, draw an arc on top and bottom of OA With A as center and same radius as before, draw an arc on top and bottom of OA 2. Where the two arcs intersect above OA is point X and where the two arcs intersect below OA is point Y Join XY Thus, XY is the perpendicular bisector of OA Now, we draw perpendicular bisector of OB Drawing perpendicular bisector of OB We follow these steps 1. With O as center, and radius more than half OB, draw an arc on top and bottom of OB With B as center and same radius as before, draw an arc on top and bottom of OB 2. Where the two arcs intersect above OB is point M and where the two arcs intersect below OB is point N Join MN Thus, MN is the perpendicular bisector of OB Now, Point where XY and MN meet is point P We need to check if PA = PB Joining PA and PB Checking length of PA and PB by compass, We note that their lengths are equal ∴ PA = PB

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.