# Ex 14.5, 8 - Chapter 14 Class 6 Practical Geometry

Last updated at Sept. 28, 2018 by Teachoo

Last updated at Sept. 28, 2018 by Teachoo

Transcript

Ex 14.5, 8 Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet? Let’s first draw a circle of radius 3.4 cm We follow these steps 1. Mark point O as center 2. First we make circle of radius 4 cm Since radius is 4 cm, we measure 4 cm using ruler and compass 3. Now keeping compass opened the same length. We keep pointed end at the center, and draw a circle using the pencil end of the compass So, this is the required circle with center O and radius = 4 cm Now, we need to draw two chords. Let two chords be AB & CD We need to draw perpendicular bisectors of AB & CD Drawing perpendicular bisector of AB We follow these steps 1. With A as center, and radius more than half AB, draw an arc on top and bottom of AB With B as center and same radius as before, draw an arc on top and bottom of AB 2. Where the two arcs intersect above AB is point P and where the two arcs intersect below AB is point Q Join PQ Thus, PQ is the perpendicular bisector of AB Now, we draw perpendicular bisector CD Drawing perpendicular bisector of CD We follow these steps 1. With C as center, and radius more than half CD, draw an arc on top and bottom of CD. With D as center and same radius as before, draw an arc on top and bottom of CD 2. Where the two arcs intersect above CD is point R and where the two arcs intersect below CD is point S Join RS Thus, RS is the perpendicular bisector of CD We note that, Perpendicular bisectors of both chords meet at the center of the circle

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.