Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 5.3, 9 - Chapter 5 Class 8 Squares and Square Roots
Last updated at May 29, 2023 by Teachoo
Ex 5.3
Ex 5.3, 1 (i)
Ex 5.3, 1 (ii) Important
Ex 5.3, 1 (iii) Important
Ex 5.3, 1 (iv)
Ex 5.3, 2 (i) Important
Ex 5.3, 2 (ii)
Ex 5.3, 2 (iii) Important
Ex 5.3, 2 (iv)
Ex 5.3, 3 Important
Ex 5.3, 4 (i)
Ex 5.3, 4 (ii)
Ex 5.3, 4 (iii) Important
Ex 5.3, 4 (iv)
Ex 5.3, 4 (v) Important
Ex 5.3, 4 (vi)
Ex 5.3, 4 (vii) Important
Ex 5.3, 4 (viii) Important
Ex 5.3, 4 (ix)
Ex 5.3, 4 (x) Important
Ex 5.3, 5 (i)
Ex 5.3, 5 (ii) Important
Ex 5.3, 5 (iii)
Ex 5.3, 5 (iv) Important
Ex 5.3, 5 (v) Important
Ex 5.3, 5 (vi)
Ex 5.3, 6 (i)
Ex 5.3, 6 (ii) Important
Ex 5.3, 6 (iii)
Ex 5.3, 6 (iv) Important
Ex 5.3, 6 (v)
Ex 5.3, 6 (vi)
Ex 5.3, 7 Important
Ex 5.3, 8
Ex 5.3, 9 Important You are here
Ex 5.3, 10
Transcript
Ex 5.3, 9 Find the smallest square number that is divisible by each of the numbers 4, 9 and 10. Smallest square number divisible by 4, 9 and 10 = L.C.M of 4, 9 and 10 OR Multiple of L.C.M Finding L.C.M of 4, 9, 10 L.C.M of 4, 9, 10 = 2 × 2 × 3 × 3 × 5 = 4 × 9 × 5 = 180 Checking if 180 is a perfect square We see that 180 = 2 × 2 × 3 × 3 × 5 Since 5 is not in pair, ∴ 180 is not a perfect square. So, we multiply by 5 to make pairs So, our number becomes 180 × 5 = 2 × 2 × 3 × 3 × 5 × 5 900 = 2 × 2 × 3 × 3 × 5 × 5 Now, it becomes a perfect square. Thus, required number is 900
