# Ex 6.3, 6 (ii) - Chapter 6 Class 8 Squares and Square Roots

Last updated at Aug. 31, 2021 by Teachoo

Last updated at Aug. 31, 2021 by Teachoo

Transcript

Ex 6.3, 6 For each of the following numbers, find the smallest whole number by which it should be divided so as to get a perfect square. Also find the square root of the square number so obtained. (ii) 2925Prime factorizing 2925 We see that , 2925 = 3 × 3 × 5 × 5 × 13 Since 13 does not occur in pairs, we divide by 13 to make it a pair So, our number becomes 2925 × 𝟏/𝟏𝟑 = 3 × 3 × 5 × 5 × 13 × 𝟏/𝟏𝟑 225 = 3 × 3 × 5 × 5 Square root of 225 :- ∴ √225 = 3 × 5 = 15 ∴ The smallest whole number to be divided = 13 and square root of new number = 15

Ex 6.3

Ex 6.3, 1 (i)

Ex 6.3, 1 (ii)

Ex 6.3, 1 (iii)

Ex 6.3, 1 (iv)

Ex 6.3, 2 (i) Important

Ex 6.3, 2 (ii)

Ex 6.3, 2 (iii)

Ex 6.3, 2 (iv)

Ex 6.3, 3 Important

Ex 6.3, 4 (i) Important

Ex 6.3, 4 (ii)

Ex 6.3, 4 (iii)

Ex 6.3, 4 (iv)

Ex 6.3, 4 (v)

Ex 6.3, 4 (vi)

Ex 6.3, 4 (vii)

Ex 6.3, 4 (viii)

Ex 6.3, 4 (ix)

Ex 6.3, 4 (x)

Ex 6.3, 5 (i)

Ex 6.3, 5 (ii)

Ex 6.3, 5 (iii)

Ex 6.3, 5 (iv)

Ex 6.3, 5 (v)

Ex 6.3, 5 (vi)

Ex 6.3, 6 (i)

Ex 6.3, 6 (ii) You are here

Ex 6.3, 6 (iii)

Ex 6.3, 6 (iv)

Ex 6.3, 6 (v)

Ex 6.3, 6 (vi)

Ex 6.3, 7

Ex 6.3, 8

Ex 6.3, 9

Ex 6.3, 10 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.