# Ex 6.3, 5 (vi) - Chapter 6 Class 8 Squares and Square Roots

Last updated at Aug. 31, 2021 by Teachoo

Last updated at Aug. 31, 2021 by Teachoo

Transcript

Ex 6.3, 5 For each of the following numbers, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained. (vi) 768 Prime factorizing 768 By prime factorization, 768 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 Since 3 does not occur in pair we multiply by 3 to make it a pair So, our number becomes 768 × 3 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 2304 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 Square root of 2304 ∴ √2304 = 2 × 2 × 2 × 2 × 3 = 4 × 4 × 3 = 48 ∴ The smallest whole number to be multiplied = 3 and square root of new number = 48

Ex 6.3

Ex 6.3, 1 (i)

Ex 6.3, 1 (ii)

Ex 6.3, 1 (iii)

Ex 6.3, 1 (iv)

Ex 6.3, 2 (i) Important

Ex 6.3, 2 (ii)

Ex 6.3, 2 (iii)

Ex 6.3, 2 (iv)

Ex 6.3, 3 Important

Ex 6.3, 4 (i) Important

Ex 6.3, 4 (ii)

Ex 6.3, 4 (iii)

Ex 6.3, 4 (iv)

Ex 6.3, 4 (v)

Ex 6.3, 4 (vi)

Ex 6.3, 4 (vii)

Ex 6.3, 4 (viii)

Ex 6.3, 4 (ix)

Ex 6.3, 4 (x)

Ex 6.3, 5 (i)

Ex 6.3, 5 (ii)

Ex 6.3, 5 (iii)

Ex 6.3, 5 (iv)

Ex 6.3, 5 (v)

Ex 6.3, 5 (vi) You are here

Ex 6.3, 6 (i)

Ex 6.3, 6 (ii)

Ex 6.3, 6 (iii)

Ex 6.3, 6 (iv)

Ex 6.3, 6 (v)

Ex 6.3, 6 (vi)

Ex 6.3, 7

Ex 6.3, 8

Ex 6.3, 9

Ex 6.3, 10 Important

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.