Ex 6.3, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 11

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Ex 6.3, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 12

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  1. Chapter 6 Class 8 Squares and Square Roots
  2. Serial order wise

Transcript

Ex 6.3, 5 For each of the following numbers, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained. (vi) 768 Prime factorizing 768 By prime factorization, 768 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 Since 3 does not occur in pair we multiply by 3 to make it a pair So, our number becomes 768 × 3 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 2304 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 Square root of 2304 ∴ √2304 = 2 × 2 × 2 × 2 × 3 = 4 × 4 × 3 = 48 ∴ The smallest whole number to be multiplied = 3 and square root of new number = 48

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.