Question 7 Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C . Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?Dinesh
Dinesh went from A to B to C
Total distance = AB + BC
= 7.5 + 12.7
= 75/10 + 127/10
Ayub
Ayub went from A to D to C
Total distance = AD + DC
= 9.3 + 11.8
= 93/10 + 118/10
= ((75 + 127))/10
= ((127 + 75))/10
= 202/10
= 20.2 km
= ((93 + 118))/10
= ((118 +93))/10
= 211/10
= 21.1 km
We need to find
who travelled more
So, we need to find greater of 20.2 & 21.1
Comparing digits before decimal point
20 < 21
So, 20.2 < 21.1
Thus, Ayub travelled more
We also need to find by how much
Difference in distance = 21.1 − 20.2
= 211/10 − 202/10
= (211 − 202)/10
= 9/10
= 0. 9 km
Converting into m
= 0.9 × 1 km
= 0.9 × 1000 m
= 9/10 × 1000 m
= 9 × 100 m
= 900 m
So, Ayub travelled more by 900 m
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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