Check sibling questions

Ex 2.5, 7 - Dinesh went from place A to place B and from there to

Ex 2.5, 7 - Chapter 2 Class 7 Fractions and Decimals - Part 2
Ex 2.5, 7 - Chapter 2 Class 7 Fractions and Decimals - Part 3 Ex 2.5, 7 - Chapter 2 Class 7 Fractions and Decimals - Part 4


Transcript

Ex 2.5, 7 Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C . Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?Dinesh Dinesh went from A to B to C Total distance = AB + BC = 7.5 + 12.7 = 75/10 + 127/10 Ayub Ayub went from A to D to C Total distance = AD + DC = 9.3 + 11.8 = 93/10 + 118/10 = ((75 + 127))/10 = ((127 + 75))/10 = 202/10 = 20.2 km = ((93 + 118))/10 = ((118 +93))/10 = 211/10 = 21.1 km We need to find who travelled more So, we need to find greater of 20.2 & 21.1 Comparing digits before decimal point 20 < 21 So, 20.2 < 21.1 Thus, Ayub travelled more We also need to find by how much Difference in distance = 21.1 − 20.2 = 211/10 − 202/10 = (211 − 202)/10 = 9/10 = 0. 9 km Converting into m = 0.9 × 1 km = 0.9 × 1000 m = 9/10 × 1000 m = 9 × 100 m = 900 m So, Ayub travelled more by 900 m

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.