Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 8.3, 7 - Chapter 8 Class 6 Decimals
Last updated at May 29, 2023 by Teachoo
Addition of decimal numbers - Statement questions
Chapter 8 Class 6 Decimals
Concept wise
- Definition
- Tenth
- Hundredth
- Words to decimals
- Decimals in number line
- Decimals to fractions
- Fractions to decimals
- Using Decimals - Converting to mm, cm, km, kg, rupees
- Comparing decimals
- Addition of decimal numbers
-
Addition of decimal numbers - Statement questions
- Subtraction of decimal numbers
- Subtraction of decimal numbers - Statement questions
Transcript
Ex 8.3, 7 Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850g flour. Find the total weight of his purchases.Weight of rice = 5 kg 400 g Weight of sugar = 2 kg 20 g Weight of flour = 10 kg 850 g Total weight = 5 kg 400 g + 2 kg 20 g + 10 kg 850 g = (5 kg + 400 g) + (2 kg + 20 g) + (10 kg + 850 g) = (5 kg + 2 kg + 10 kg) + (400 g + 20 g + 850 g) = 17 kg + 1270 g = 17 kg + 1000 g + 270 g As 1000 g = 1 kg = 17 kg + 1 kg + 270 g = 18 kg + 270 g = 18 kg 270 g Converting to decimals = 18 kg + 270 g = 18 kg + 270 × 1 g = 18 kg + 270 × 1/1000 kg = 18 kg + 270/1000 kg = (18+270/1000) kg = ((18 × 1000 +270)/1000) kg = (18000 + 270)/1000 kg = 18270/1000 kg = 18.270 kg
