# Ex 8.5, 5 - Chapter 8 Class 6 Decimals

Last updated at June 29, 2018 by Teachoo

Last updated at June 29, 2018 by Teachoo

Transcript

Ex 8.5, 5 Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?Distance walked in morning = 2 km 35 m Distance walked in morning = 1 km 7 m Total distance walked = Distance walked in morning + Distance walked in evening = 2 km 35 m + 1 km 7 m = (2 km + 35 m) + (1 km + 7 m) = (2 km + 1 km) + (35 m + 7 m) = 3 km + 42 m = 3 km 42 m Converting to decimals = 3 km + 42 m = 3 km + 42 × 1/1000 km = 3 km + 42/1000 km = (3+42/1000 " " ) km = ((3 × 1000 + 42)/1000 " " ) km = ((3000 + 42)/1000) km = 3042/1000 km = 3.042 km ∴ Total distance walked = 3.042 km

Addition of decimal numbers - Statement questions

Chapter 8 Class 6 Decimals

Concept wise

- Definition
- Tenth
- Hundredth
- Words to decimals
- Decimals in number line
- Decimals to fractions
- Fractions to decimals
- Using Decimals - Converting to mm, cm, km, kg, rupees
- Comparing decimals
- Addition of decimal numbers
- Addition of decimal numbers - Statement questions
- Subtraction of decimal numbers
- Subtraction of decimal numbers - Statement questions

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.