Ex 8.1, 10 - Write rational numbers in ascending order (i) -3/5, -2/5 - Ex 8.1

part 2 - Ex 8.1, 10 - Ex 8.1 - Serial order wise - Chapter 8 Class 7 Rational Numbers

part 3 - Ex 8.1, 10 - Ex 8.1 - Serial order wise - Chapter 8 Class 7 Rational Numbers

part 4 - Ex 8.1, 10 - Ex 8.1 - Serial order wise - Chapter 8 Class 7 Rational Numbers
part 5 - Ex 8.1, 10 - Ex 8.1 - Serial order wise - Chapter 8 Class 7 Rational Numbers

part 6 - Ex 8.1, 10 - Ex 8.1 - Serial order wise - Chapter 8 Class 7 Rational Numbers part 7 - Ex 8.1, 10 - Ex 8.1 - Serial order wise - Chapter 8 Class 7 Rational Numbers

  

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Ex 8.1, 10 Write the following rational numbers in ascending order: (i) (−3)/5, (−2)/5 , (−1)/5 (−3)/5, (−2)/5 , (−1)/5 Since all numbers are negative We ignore the signs 3/5, 2/5, 1/5 Since denominator is same, Number with greater numerator is greater 3/5 > 2/5 > 1/5 3/5 > 2/5 > 1/5 Multiplying –1 both sides 3/5 × –1 < 2/5 × –1 < 1/5 × –1 (−𝟑)/𝟓 < (−𝟐)/𝟓 < (−𝟏)/𝟓 So, in ascending order Ex 8.1, 10 Write the following rational numbers in ascending order: (ii) (−1)/3, (−2)/9 , (−4)/3 (−1)/3, (−2)/9 , (−4)/3 Making denominator same (−1)/3 = (−4)/3 = So, our numbers are (−3)/9, (−2)/9, (−12)/9 Since all numbers are negative, Ignoring signs 𝟑/𝟗, 𝟐/𝟗, 𝟏𝟐/𝟗 Since denominator is same, Number with greater numerator is greater 12/9 > 3/9 > 2/9 Multiplying –1 both sides 12/9 × –1 < 3/9 × –1 < 2/9 × –1 (−12)/9 < (−3)/9 < (−2)/9 i.e. (−4)/3 < (−1)/3 < (−2)/9 So, in ascending order (−𝟒)/𝟑, (−𝟏)/𝟑, (−𝟐)/𝟗 Ex 8.1, 10 Write the following rational numbers in ascending order: (iii) (−3)/7, (−3)/2 , (−3)/4(−3)/7, (−3)/2 , (−3)/4 Since all numbers are negative, Ignoring the signs 3/7, 3/2, 3/4 Since all number have same numerator, Number with smaller denominator is greater Rough 10/2, 10/5, 10/10 have same numerator 10/2 = 5 10/5 = 2 10/10 = 1 So, number with smaller denominator is larger So, 3/2 > 3/4 > 3/7 Multiplying –1 both sides 3/2 × –1 < 3/4 × –1 < 3/7 × –1 (−𝟑)/𝟐 < (−𝟑)/𝟒 < (−𝟑)/𝟕 So, in ascending order (−3)/2, (−3)/4, (−3)/7

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo