We do not leave an irrational number in the denominator.
So, we rationalise the denominator.Β Let us look at some examples
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Rationalising
Add (3β2+7β3) and (β2β5β3)
Divide 5β11 by 3β33
Multiply 2β15 by 7β5
Simplify (β5+β7)^2
Simplify (β4ββ13)(β4+β13)
Simplify (9ββ3)(9+β3)
Simplify (3β5β5β2)(4β5+3β2)
Rationalise the denominator of 8/β7
Rationalise the denominator of 1/((8 + 5β2))
Simplify (7β3)/(β10 + β3)β(2β5)/(β6 + β5)β(3β2)/(β15 + 3β2)
Multiple Choice Questions - Chapter 1 Class 9 Maths
Example 16
If a and b are rational numbers and (β11 β β7)/(β11 + β7) = a β bβ77, find the value of a and b
Example 17
Find the values of a and b if (7 + 3β5)/(3 + β5) β (7 β 3β5)/(3 β β5) = a+β5 b
Ex 1.4, 5 (i) Deleted for CBSE Board 2024 Exams
If x = 1/(2 β β3), find the value of x^3 β 2x^2 β 7x + 5
If a = 5 + 2β6 and b = 1/a, then what will be the value of a^2+b^2 ?
Example 18
Example 19 Important
Rationalising
Last updated at May 29, 2023 by Teachoo
We do not leave an irrational number in the denominator.
So, we rationalise the denominator.Β Let us look at some examples
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Some Identities (βπ)^2=π β(π^2 )=π βππ=βπ Γβπ β(π/π)=βπ/βπ (βπββπ)(βπ+βπ)=πβπ (πββπ)(π+βπ)=π^2βπ (βπ+βπ)^2=π+π+2βππ (βπ+βπ)(βπ+βπ)=βππ+βππ + βππ + βππ