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Examples

Example 1
Deleted for CBSE Board 2023 Exams

Example 2 Important Deleted for CBSE Board 2023 Exams

Construction 11.1 Important Deleted for CBSE Board 2023 Exams

Construction 11.2 Deleted for CBSE Board 2023 Exams

Construction 11.3 Important Deleted for CBSE Board 2023 Exams You are here

How to construct Tangents to circle if center of circle is not given? Important Deleted for CBSE Board 2023 Exams

Last updated at July 15, 2020 by Teachoo

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Construction 11.3 To construct the tangents to a circle from a point outside it. We are given a circle with center O and point P outside the circle We need to draw tangents from point P to the circle Let’s follow these steps Steps of construction Join PO. Make perpendicular bisector of PO Let M be the midpoint of PO. Taking M as centre and MO as radius, draw a circle. Let it intersect the given circle at points Q and R. Join PQ and PR. Then, PQ and PR are the required two tangents. Justification We need to prove that PQ and PR are the tangents to the circle. Join OQ and OR. Now, ∠PQO is an angle in the semi-circle of the blue circle And we know that, Angle in a semi-circle is a right angle. ∴ ∠PQO = 90° ⇒ OQ ⊥ PQ Since OQ is the radius of the circle, PQ has to be a tangent of the circle. Similarly, PR is a tangent of the circle.