Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Examples

Example 1
Deleted for CBSE Board 2024 Exams

Example 2 Important Deleted for CBSE Board 2024 Exams

Construction 11.1 Important Deleted for CBSE Board 2024 Exams You are here

Construction 11.2 Deleted for CBSE Board 2024 Exams

Construction 11.3 Important Deleted for CBSE Board 2024 Exams

How to construct Tangents to circle if center of circle is not given? Important Deleted for CBSE Board 2024 Exams

Constructions

Serial order wise

Last updated at May 29, 2023 by Teachoo

Construction 11.1 To divide a line segment in a given ratio. Let us divide a line segment AB into 3:2 ratio. Steps of construction: Draw line segment AB Draw any ray AX, making an acute angle (angle less than 90Β°) with AB. Mark 5 (= 3 + 2) points π΄_1, π΄_2, π΄_3, π΄_4 and π΄_5 on AX, so that γπ΄π΄γ_1=γπ΄_1 π΄γ_2=γπ΄_2 π΄γ_3=γπ΄_3 π΄γ_4=γπ΄_4 π΄γ_5 by drawing equal arcs Join γπ΅π΄γ_5. Since we want the ratio 3 : 2, Through point π΄_3 (m = 3), we draw a line parallel to π΄_5 π΅ by making β AA5B = β AA3C So, we copy β AA5B from point A3 Thus, AC : CB = 3 : 2. Justification Since β AA5B = β AA3C, So, for lines A3C and A5B, with AX as transversal, corresponding angles are equal β΄ A3C is parallel to A5B Now, Since π΄_3 πΆ is parallel to π΄_5 π΅, γπ΄π΄γ_3/(π΄_3 π΄_5 )=π΄πΆ/πΆπ΅ By construction, γπ΄π΄γ_3/(π΄_3 π΄_5 )=3/2. Therefore, π΄πΆ/πΆπ΅=3/2 Thus, C divides AB in the ratio 3 : 2.