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Ex 11.1, 1 - Draw a line segment of length 7.6 cm and divide in ratio

Ex 11.1, 1 - Chapter 11 Class 10 Constructions - Part 2
Ex 11.1, 1 - Chapter 11 Class 10 Constructions - Part 3 Ex 11.1, 1 - Chapter 11 Class 10 Constructions - Part 4 Ex 11.1, 1 - Chapter 11 Class 10 Constructions - Part 5 Ex 11.1, 1 - Chapter 11 Class 10 Constructions - Part 6

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Transcript

Question 1 Draw a line segment length 7.6 cm and divide it in the ratio 5 : 8. Measure the two parts. Give the justification of the construction. Steps of construction: Draw line segment AB of length 7.6 cm Draw any ray AX, making an acute angle with AB. Mark 13 (= 5 + 8) points 𝐴_1, γ€– 𝐴〗_2, 𝐴_3, 𝐴_4……. 𝐴_13, on AX such that 〖𝐴𝐴〗_1=𝐴_1 𝐴_2=𝐴_2 𝐴_3……. by drawing equal arcs Join 〖𝐡𝐴〗_13. Since we want the ratio 5 : 8, Through point 𝐴_5 (m = 5), we draw a line parallel to 𝐴_13 𝐡 by making ∠ AA5B = ∠ AA13C So, we copy ∠ AA13B from point A5 Note: Check how to copy an angle from Chapter 14 Class 6 Thus, AC : CB = 5 : 8. On measuring AC and BC by scale. AC = 2.9 cm & BC = 4.7 cm Justification Since ∠ AA13B = ∠ AA5C, So, for lines A13B and A5C, with AX as transversal, corresponding angles are equal ∴ A13B is parallel to A5C Now, Since A13B is parallel to A5C, 〖𝐴𝐴〗_5/(𝐴_5 𝐴_13 )=𝐴𝐢/𝐢𝐡 (By Basic Proportionality Theorem) By construction, 〖𝐴𝐴〗_5/(𝐴_5 𝐴_13 )= 5/8 Therefore, 𝐴𝐢/𝐢𝐡= 5/8 Thus, C divides AB in the ratio 5 : 8

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.