Example 2 - Minimise Z = 200x + 500y subject to x + 2y > 10 - Linear equations given - Bounded

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  1. Chapter 12 Class 12 Linear Programming
  2. Serial order wise
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Example 2 Solve the following linear programming problem graphically: Minimise Z = 200 x + 500 y subject to the constraints: x + 2y ≥ 10 3x + 4y ≤ 24 x ≥ 0, y ≥ 0 Minimize Z – 200x + 500y Subject to, x + 2y ≥ 10 3x + 4y ≤ 24 x ≥ 0, y ≥ 0 Hence Z is minimum at (4, 3)

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