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Last updated at Dec. 17, 2018 by Teachoo
Example 5 - Chapter 2 Class 12 Linear Programming - NCERT Minimise Z = 3x + 2y subject to the constraints: x + y ≥ 8 3x + 5y ≤ 15 x ≥ 0, y ≥ 0 Plotting points For x + y ≥ 8 Points are (0, 8) and (8, 0) For 3x + 5y ≤ 15 Points are (0, 3) and (5, 0) Plotting graphs of both lines And shading the relevant parts We notice that There is no common region, thus, there is no feasible region. Hence, there is no maxnimum value of Z