Ex 13.2, 6 - Chapter 13 Class 11 Statistics

Last updated at July 14, 2026 by

Ex 13.2, 6 - Find mean, standard deviation using short-cut - Ex 13.2

part 2 - Ex 13.2, 6 - Ex 13.2 - Serial order wise - Chapter 13 Class 11 Statistics

Remove Ads Share on WhatsApp

Transcript

Ex 13.2, 6 Find the mean and standard deviation using short-cut method. Mean = a + (āˆ‘ā–’š‘“š‘–š‘¦š‘–)/(āˆ‘ā–’š‘“š‘–) Ɨ h = 64 + 0/100 Ɨ1 = 64 Standard Deviation = ā„Ž/š‘ āˆš(š‘āˆ‘ā–’š‘“š‘–š‘¦š‘–2 āˆ’ (āˆ‘ā–’š‘“š‘–š‘¦š‘–)^2 ) "= " 1/100 āˆš("100" Ɨ"286 ā€“ " 怖(0)怗^2 ) = 1/100 āˆš28600 = 169.1/100 = 1.691

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.