Ex 13.2, 6 - Chapter 13 Class 11 Statistics

Last updated at August 17, 2026 by

Ex 13.2, 6 - Find mean, standard deviation using short-cut - Ex 13.2

part 2 - Ex 13.2, 6 - Ex 13.2 - Serial order wise - Chapter 13 Class 11 Statistics

Remove Ads Take short quiz All Quiz and Worksheets
Teachoo ยท Class 11 Explore Class 11

Transcript

Ex 13.2, 6 Find the mean and standard deviation using short-cut method. Mean = a + (โˆ‘โ–’๐‘“๐‘–๐‘ฆ๐‘–)/(โˆ‘โ–’๐‘“๐‘–) ร— h = 64 + 0/100 ร—1 = 64 Standard Deviation = โ„Ž/๐‘ โˆš(๐‘โˆ‘โ–’๐‘“๐‘–๐‘ฆ๐‘–2 โˆ’ (โˆ‘โ–’๐‘“๐‘–๐‘ฆ๐‘–)^2 ) "= " 1/100 โˆš("100" ร—"286 โ€“ " ใ€–(0)ใ€—^2 ) = 1/100 โˆš28600 = 169.1/100 = 1.691

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.