Ex 9.3, 9 - Find general solution: dy/dx = sin-1 x - Chapter 9 - Ex 9.3

part 2 - Ex 9.3, 9 - Ex 9.3 - Serial order wise - Chapter 9 Class 12 Differential Equations
part 3 - Ex 9.3, 9 - Ex 9.3 - Serial order wise - Chapter 9 Class 12 Differential Equations

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Transcript

Ex 9.3, 9 For each of the differential equations in Exercises 1 to 10, find the general solution : ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ=sin^(โˆ’1)โก๐‘ฅ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ=sin^(โˆ’1)โก๐‘ฅ ๐‘‘๐‘ฆ = sin^(โˆ’1)โก๐‘ฅ dx Integrating both sides โˆซ1โ–’ใ€–๐’…๐’š ใ€—= โˆซ1โ–’ใ€–ใ€–๐ฌ๐ข๐งใ€—^(โˆ’๐Ÿ)โกใ€–๐’™.๐Ÿ ๐’…๐’™ใ€— ใ€— Integrating by parts, using formula โˆซ1โ–’ใ€–๐‘“ (๐‘ฅ)๐‘”(๐‘ฅ)๐‘‘๐‘ฅ ใ€—= ๐‘“(๐‘ฅ) โˆซ1โ–’ใ€–๐‘”(๐‘ฅ)๐‘‘๐‘ฅ โˆ’โˆซ1โ–’ใ€–[๐‘“โ€ฒ(๐‘ฅ)โˆซ1โ–’๐‘”(๐‘ฅ)๐‘‘๐‘ฅ] ๐‘‘๐‘ฅ ใ€— ใ€— Take f(x) = sinโˆ’1 x and g(x) = 1 y = x ใ€–๐’”๐’Š๐’ใ€—^(โˆ’๐Ÿ) ๐’™ โˆ’ โˆซ1โ–’๐’™/โˆš(๐Ÿ โˆ’ ๐’™^๐Ÿ ) dx Let t = 1 โˆ’ x2 dt = โˆ’2xdx x dx = (โˆ’๐‘‘๐‘ก)/2 Hence, our equation becomes y = x sinโˆ’1 x โˆ’ โˆซ1โ–’(โˆ’๐‘‘๐‘ก)/(2โˆš๐‘ก) y = x sinโˆ’1 x + โˆซ1โ–’๐‘‘๐‘ก/(2โˆš๐‘ก) y = x sinโˆ’1 x + ๐Ÿ/๐Ÿ โˆซ1โ–’ใ€–๐’•^((โˆ’๐Ÿ)/๐Ÿ) ๐’…๐’•ใ€— y = x sinโˆ’1 x + ๐Ÿ/๐Ÿ ๐’•^((โˆ’๐Ÿ)/๐Ÿ + ๐Ÿ)/((โˆ’๐Ÿ)/๐Ÿ + ๐Ÿ) + C y = x sinโˆ’1 x + 1/2 (๐‘ก^(1/2) )/((1/2) )+๐ถ y = x sinโˆ’1 x + โˆš๐‘ก + C Putting back value of t y = x sinโˆ’1 x + โˆš(๐Ÿโˆ’๐’™^๐Ÿ ) + C y = sinโˆ’1 x โˆซ1โ–’ใ€–๐Ÿ ๐’…๐’™ โˆ’โˆซ1โ–’[๐Ÿ/โˆš(๐Ÿ โˆ’ ๐’™^๐Ÿ ) โˆซ1โ–’ใ€–๐Ÿ.๐’…๐’™ ใ€—] ใ€— dx

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