Ex 9.3, 6 - Find general solution: dy/dx = (1 + x2) (1 + y2) - Ex 9.3

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Ex 9.3, 6 For each of the differential equations in Exercises 1 to 10, find the general solution : 𝑑𝑦/𝑑π‘₯=(1+π‘₯^2 )(1+𝑦^2 )𝑑𝑦/𝑑π‘₯=(1+π‘₯^2 )(1+𝑦^2 ) dy = (1+π‘₯^2 )(1+𝑦^2 ) dx π’…π’š/(𝟏 + π’š^𝟐 )= (1 + 𝒙^𝟐) dx Integrating both sides. ∫1▒𝑑𝑦/(1 + 𝑦^2 ) = ∫1β–’(1+π‘₯2)𝑑π‘₯ tanβˆ’1 y = x + 𝒙^πŸ‘/πŸ‘ + C (∫1β–’1/(1+𝑦^2 ) dy = tanβˆ’1 y)

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