Slide107.JPG

Slide108.JPG


Transcript

Ex 9.2, 1 Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation : 𝑦=𝑒^π‘₯+1 : 𝑦^β€²β€²βˆ’π‘¦^β€²=0 π’š=𝒆^𝒙+𝟏 Now, π’š^β€²=𝑑𝑦/𝑑π‘₯=𝑑/𝑑π‘₯Solving L.H.S π’š^β€²β€²βˆ’π’š^β€² =𝑒^π‘₯βˆ’π‘’^π‘₯ =0 = R.H.S Hence verified. Solving L.H.S π’š^β€²β€²βˆ’π’š^β€² =𝑒^π‘₯βˆ’π‘’^π‘₯ =0 = R.H.S Hence verified.

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.